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Python Notes

Quick Introduction

Python is an interpreted programming language where codes go through a program called interpreter, which reads and executes the code line by line.

  • Flexible
  • Platform independent

Python is popular for

  • Machine Learning (PyTorch, TensorFlow)
  • Data Science (numpy, pandas, matplotlib, scikit-learn)
  • Large-scale web application (Django).

Install Python

Virtual Environment

It’s recommended to create a virtual environment for each of your project.

Python Venv

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$ python -m venv /path/to/new/virtual/environment

# Example
$ pwd
/Users/zheng/Documents/demo
$ python -m venv project_venv
# Activate venv
$ source project_venv/bin/activate
# Verify
$ which python
/Users/zheng/Documents/demo/project_venv/bin/python

Anaconda/Miniconda Venv

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# Create venv
# https://docs.conda.io/projects/conda/en/latest/commands/create.html
$ conda create -n project_venv python=3.11
# List conda venvs
$ conda env list
base                  *  /Users/zheng/miniconda3
CV                       /Users/zheng/miniconda3/envs/CV
Django                   /Users/zheng/miniconda3/envs/Django
# Activate venv
$ conda activate CV

Install Python Libraries

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pip install <lib_name>

With the flag -i, you can specify *PyPi (The Python Package Index)

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# A collection of PyPi for users in China
# -----------------------------------------------------#
https://pypi.tuna.tsinghua.edu.cn/simple/
https://mirrors.aliyun.com/pypi/simple/
https://repo.huaweicloud.com/repository/pypi/simple/
# -----------------------------------------------------#

# Example
pip install -i https://pypi.tuna.tsinghua.edu.cn/simple/ numpy

Variables

Python Variable Names

Naming Conventions:link:

  • Must start with a letter [A-z] or _
  • Can NOT start with a number[0-9]
  • Contain ONLY [A-z], [0-9] and _
  • Are case-sensitive Namename

Numerical Variables

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# Define variables
>>> a = 2
>>> b = 10
>>> c = 3

# 1. Numerical Operations: 
#	 +-*/
# 2. Power
>>> a ** b
1024
# 3. Mod
>>> b % c
1
# 4. To string variables
>>> str(a)
'2'

*You can get get the type of any variable with type(<var_name>)

String Variables

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# Define variables
>>> a = "TeSt"
>>> b = "2"

# 1. title(), lower() and upper() methods
>>> a.title()
'Test'
>>> a.lower()
'test'
>>> a.upper()
'TEST'

# 2. strip(), lstrip() and rstrip() methods
>>> c = ",.+-* TeSt *-+.,"
>>> c.strip(",.+-* ")
'TeSt'
>>> c.lstrip(",.+-* ")
'TeSt *-+.,'
>>> c.rstrip(",.+-* ")
',.+-* TeSt'

# 3. Combine strings together
>>> a + " " + b
'TeSt 2'

# 4. To other types
>>> int(b)
2
>>> float(b)
2.0

Loops

Loop with if

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if condition_1:
    function_1
    return return_value
elif condition_2:
    function_2
    return return_value
else condition_3:
    function_3
    return return_value

Loop with while

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while condition:
    function
    if break_condition:
        break
    if continue_condition:
        continue
    if pass_condition:
        pass
  • Break will terminate the loop
  • Continue will only terminate/skip the current iteration
  • Pass is typically used as a placeholder for future code

Normal Function Arguments

Parameters are placeholders in a function definition, while Arguments are actual values passed during function invocation

Defining Your Own Python Function :link:

Positional Arguments

  • Internally, values in *args as represented as in a tuple
  • The name args can be named arbitrarily
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def cal_average(*int_nums):
    sum = 0
    for item in int_nums:
        sum += item
    return sum / len(int_nums)

>>> cal_average(1, 2)
1.5
>>> cal_average(*[i for i in range(10)])
4.5

Keyword Arguments

  • Internally, values in **kwargs as represented as in a dict
  • The name kwargs can be named arbitrarily
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def learn_kwargs(**kwargs):
    print(kwargs)
    print(type(kwargs))
    for key, val in kwargs.items():
        print(f"{key} -> {val}")

>>> learn_kwargs(first_name='Zheng', last_name='Yuan')
{'first_name': 'Zheng', 'last_name': 'Yuan'}
<class 'dict'>
first_name -> Zheng
last_name -> Yuan

All-in-One

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def aio_func(a, b, *args, **kwargs):
    print(a)
    print(b)
    print(args)
    print(kwargs)


>>> aio_func(1, 2, 3, 4, 5, first_name='Zheng', last_name='Yuan')
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(3, 4, 5)
{'first_name': 'Zheng', 'last_name': 'Yuan'}

# a, b are positional arguments
# 3, 4, 5 are also positional arguments
# first_name, last_name are keyword arguments

X-Only Function Arguments

Why do we need them?

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# Q: In the following function, how to give the prefix a default value?
def concat(prefix, *args):
    print(f'{prefix}{".".join(args)}')

>>> concat('//', 'a', 'b', 'c')
//a.b.c


# 1. Try-1
def concat(prefix='-> ', *args):
    print(f'{prefix}{".".join(args)}')

>>> concat('a', 'b', 'c')
ab.c
# This won't work because prefix is a positional argument, so when invoking
# the function call, 'a' will replace the default value '-> '. 
# Actually, the default value can never be reached.

# 2. Try-2
>>> concat(prefix='//', 'a', 'b', 'c')
	 File "<stdin>", line 1
    concat(prefix='//', 'a', 'b', 'c')
                                     ^
SyntaxError: positional argument follows keyword argument
# This also won't work, because python requires keyword arguments after 
# positional arguments

# 3. Try-3
>>> concat('a', 'b', 'c', prefix='... ')
	File "<stdin>", line 1, in <module>
TypeError: concat() got multiple values for argument 'prefix'
# As Try-1, 'a' is thought to be the positional argument prefix, but it's given again.

# This only works for python3
def concat(*args, prefix='-> '):
	print(f'{prefix}{".".join(args)}')
    
>>> concat('a', 'b', 'c')
-> a.b.c


def concat(*args, prefix='-> ', sep='.'):
    print(f'{prefix}{sep.join(args)}')
    
>>> concat('a', 'b', 'c', prefix='//', sep='-')
//a-b-c

# In examples above, prefix and sep are both keyword-only arguments

Keyword-Only Arguments

The bare variable argument parameter * indicates that there aren’t any more positional parameters.

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def oper(x, y, *, op='+'):
    if op == '+':
        return x + y
    elif op == '-':
        return x - y
    elif op == '/':
        return x / y
    else:
        return None
 
>>> oper(3, 4, '+')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: oper() takes 2 positional arguments but 3 were given

>>> oper(3, 4, "I don't belong here")
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: oper() takes 2 positional arguments but 3 were given
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# https://peps.python.org/pep-3102/
# Old syntax and fix
def compare(a, b, *ignore, key=None):
    # The ‘ignore’ argument will also suck up any erroneous positional arguments
    if ignore:
        raise TypeError
    do_smth

# New syntax
def compare(a, b, *, key=None):
    do_smth

Positional-Only Arguments

Python 3.8: Cool New Features for You to Try :link:

The bare variable argument parameter / indicates that parameters before it are positional-only (cannot be passed by keyword) and parameters after it are regular arguments that can be passed either by position or keyword.

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# Python 3.8
def f(x, /, y):
    print(x)
    print(y)

>>> f(x=1, y=2)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: f() got some positional-only arguments passed as keyword arguments: 'x'

>>> f(1, y=2)
1
2

>>> f(1, 2)
1
2

All-in-One

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def f(a, b, c, /, d, e, */, f, g):
    do_smth

# a, b, c are postitional-only arguments
# d, e are normal arguments
# f, g are keyword-only arguments

Metaprogramming

Metaprogramming is about creating functions and classes whose main goal is to manipulate code.

Decorators

Primer on Python Decorators :link:

PEP 318 – Decorators for Functions and Methods :link:

Decorators wrap a function, modifying its behavior.

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def my_decorator(func):
    def wrapper_func(*args, **kwargs):
        do_smth
        result = func(*args, **kwargs)
        do_smth
        return result
    return wrapper_func
    
def foo_func():
    do_smth
    
# 1. The complicated way
result = my_decorator(foo_func(my_args, my_kwargs))

# 2. The easy way
@my_decorator
def foo_func():
    do_smth
    
results = foo_func(my_args, my_kwargs)

Problem: Important metadata such as the name, doc string, annotations, and calling signatures are lost. Workarounds \(\longrightarrow\)

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from functools import wraps

def my_decorator(func):
    @wraps
    def wrapper_func(*args, **kwargs):
        do_smth
        result = func(*args, **kwargs)
        do_smth
        return result
    return wrapper_func

Class Decorators

Meta Classes

Lambda Function

Lambda expressions in Python :link:

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# Converting a simple function
def function_name(param_1, param_2, ...):
    return do_smth

lambda param_1, param_2, ...: do_smth

# Converting a simple function with if
def function_name(param_1, param_2, ...):
    if condition:
        do_smth_1
    else:
        do_smth_2

lambda param_1, param_2: do_smth_1 if condition else do_smth_2

Function Annotations

PEP 3107 – Function Annotations

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# Some demo syntax
def demo_func(param_1: tuple = (1, 2, 3), 
              param_2: int = 1024,
              param_3: float = 1.0) -> bool:
    do_smth

Data Structure

File Operations

Object-Oriented Programming

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